If ABC is congurent PQR and AB/PQ =1/3 Find area of ABC
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Hi there!!
Since,∆ABC is Congruent to ∆PQR
=) ar∆ABC/ar∆PQR= [AB/PQ]2
-----(by area ofsimilar∆'s Theorem)
=)ar∆ABC/ar∆PQR=(1)2/(3)2
=)ar∆ABC/ar∆PQR=1/9.
Hope it helps
MARK AS BRAINLIEST PLZZZ..
Since,∆ABC is Congruent to ∆PQR
=) ar∆ABC/ar∆PQR= [AB/PQ]2
-----(by area ofsimilar∆'s Theorem)
=)ar∆ABC/ar∆PQR=(1)2/(3)2
=)ar∆ABC/ar∆PQR=1/9.
Hope it helps
MARK AS BRAINLIEST PLZZZ..
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