Question

If ∆ABC is right angled at B, what is the value of sin (A + C).



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Answer 1

$\bold{\red{sin(A+C) = sinA.cosC+sinC.cosA}}$

$\bold{sin(A+C) = \dfrac{BC}{AC}. \dfrac{AB}{AC}+ \dfrac{AB}{AC}. \dfrac{BC}{AC}}$

$\bold{sin(A+C) = \dfrac{AB.BC}{AC}+ \dfrac{AB.BC}{AC}}$

$\bold{sin(A+C) = \dfrac{2.AB.BC}{AC}}$

Answer 2

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