If ∆ABC is right angled at C, then find cos(A+B) WITH WORKING
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cos( a+ b)= cos a.cos b - sin a.sin b
=(AC/AB × BC/AB ) - (BC /AB × AC/AB)
= 0 (Ans.)
=(AC/AB × BC/AB ) - (BC /AB × AC/AB)
= 0 (Ans.)
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