If ∆ABC is right angled at C, then the value of cos (A + B)
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∆ABC is right angled at C.
The value of cos(A + B)
Since , ∆ABC is right angled at C
∴ ∠C = 90°
→ A + B + C = 180
→ A + B + 90
→ cos ( a + b ) = cos 90°
→ cos ( a+ b ) = 0
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