If abc is right angled triangle at b , the perimeter of triangle =24 cm ,and ab=6cm ,what is the angle of c ?
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Answered by
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Answer:
Step-by-step explanation:
Here, B = 90 degree
ab and bc are sides adjacent to angle b, ac is the hypotenuse.
Now, ab + bc + ac = 24 cm
or, 6 + bc + ac = 24
or, bc + ac = 18
ac must be greater than bc (as hypotenuse)
So, ac = 10 cm
bc = 8 cm
so, tanC = (6/8)
or, C = 36.87 degree
Answered by
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Step-by-step explanation:
angle of C is
ab=6cm
other sides=24-6=18
let other sides=x+y=18
using pythagoras theory
ab^2+bc^2=ac^2
6^2=ac^2-bc^2
36=(ac+bc)(ac-bc)
36=(18)(x-y)
36=18 (x-(18-x))
36=18(x-18+x)
36=18(2x-18)
36=36x-324
36+324=36x
360/36=x
x=10
then
y=18-10
y=8
let find /c
sin(c)=6/10
sin(c)=0.6
sin^-1 (0.6)=c
sin^-1 (0.6)=36.8698976458
c=36.8698976458
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