if ∆ABC is similar to ∆AXY,AB/AX=5/3.if XY= 4cm and BY bisects angle XYC,find AY. it's urgent. No spamming.please
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Given : ∆ABC is similar to ∆AXY,AB/AX=5/3.if XY= 4cm and BY bisects angle XYC
To find : AY
Solution:
∆ABC is similar to ∆AXY
=> AB/AX = BC/XY = AC/AY
=> BC/XY = AC/AY = 5/3
=> BC/XY = 5/3
XY = 4
=> BC/4 = 5/3
=> BC = 20/3
∆ABC is similar to ∆AXY
=> XY ║ BC
=> ∠XYB = ∠CBY
BY Bisects ∠XYC
=> ∠XYB = ∠CYB
from both
∠CBY = ∠CYB
=> in Δ BCY
BC = CY
=> CY = 20/3
Hence AC/AY = 5/3
=> ( AY + CY)/AY = 5/3
=> (AY + 20/3)/AY = 5/3
=> 3AY + 20 = 5AY
=> 2AY = 20
=> AY = 10
AY = 10
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