if ∆abc is similar to ∆pqr, ar(∆abc)/ar(∆pqr) = 16/9, ab = 2cm & ac = 12cm, then find the value of PR.
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Step-by-step explanation:
Given ∆ABC ~ ∆QRP,
AB=18 cm , BC = 15 cm,
/* we know that,
The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides */
Therefore,
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