Question

if ∆ABC isocletriangle c=90 and AB =5cm then what the length of AC​

Answer 1

Answer:

isosceles triangle so angle a and angle c are same so let angle a and angle c be x

angle a +angle b +angle c =180

x+90+x=180

2x+90=180

2x=180-90

2x=90

x=90/2

x=45

Answer 2

Answer:

Step-by-step explanation:

Given -C=90°

ABC is an isosceles triangle

AB=BC =5cm

AC^2=AB^2+BC^2

Ac^2=(5)^2+(5)^2

=25+25

=50

AC=5✓2