Math, asked by shashankranjan027, 1 month ago

If ABC on an isosceles triangle, AB=AC and D is a point on BC such that AD⊥BC then A B2−AD2=BD⋅DC
B AB2−AD2=BD2−DC2
C AB2+AD2=BD⋅DC
D AB2+AD2=BD2−DC2

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Answered by rd596982
0

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