If ∆ABC = ∆POR with angle
A = 90° and AB = 5 cm,
AC = 12 cm, find QR.
Answer :- 13cm
plz help me guys
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✰Answer✰
AP = AQ , BP = PR and CR = CQ (tangents from an external point)
Perimeter of ∆ABC = AB + BR + RC + CA
= AB + BP + CQ + CA
= AP + AQ
= 2AP
∆APO is a right-angled triangle. AO2 = AP2 + PO2
132 = AP2 + 52
AP2 = 144
AP = 12
∴ Perimeter of ∆ABC = 24 cm
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