Question

If ∆ABC ~ ∆PQR, A(∆ABC) = 80, A(∆PQR) = 125, then find AB/PQ​

Answer 1

Answer:

Given

ΔABC∼ΔPQR

A(ΔABC)=80

A(ΔPQR)=125

According to theorem of areas of similar triangles ""When two triangles are similar, the ratio of areas of those triangles is equal to the ratio of the square of their corresponding sides'

∴

A(ΔPQR)

A(ΔABC)

=

PQ

2

AB

2

⇒

125

80

=

PQ

2

AB

2

25

16

=

PQ

2

AB

2

⇒

5

2

4

2

=

PQ

2

AB

2

⇒

PQ

AB

=

5

4

Therefore,

A(ΔPQR)

A(ΔABC)

=

125

80

and

PQ

AB

=

5

4