If ∆ABC ~∆PQR, AB /PQ = 3 /5 and ar(∆ ABC ) =225 cm2,find the area of triangle PQR
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Given
GivenAB:PQ=3:5
GivenAB:PQ=3:5area of triangle PQR=50
GivenAB:PQ=3:5area of triangle PQR=50then,
GivenAB:PQ=3:5area of triangle PQR=50then,area of triangle ABC =
GivenAB:PQ=3:5area of triangle PQR=50then,area of triangle ABC ={3/5}^2=A(ABC)/50
GivenAB:PQ=3:5area of triangle PQR=50then,area of triangle ABC ={3/5}^2=A(ABC)/509/25=A(ABC)/50
GivenAB:PQ=3:5area of triangle PQR=50then,area of triangle ABC ={3/5}^2=A(ABC)/509/25=A(ABC)/509×2=A(ABC)
GivenAB:PQ=3:5area of triangle PQR=50then,area of triangle ABC ={3/5}^2=A(ABC)/509/25=A(ABC)/509×2=A(ABC)=18
GivenAB:PQ=3:5area of triangle PQR=50then,area of triangle ABC ={3/5}^2=A(ABC)/509/25=A(ABC)/509×2=A(ABC)=18☺️☺️☺️☺️
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