Question

if ∆ ABC ~ ∆ PQR and angle ABC= 70, angle BAC =50 then angle PQR= -------------​

Answer 1

Answer:

angle PQR = 70°

Step-by-step explanation:

Given: ∆ABC ~ ∆PQR

To Find : angle PQR

Solution: Angle ABC =Angle PQR=70°

(GIVEN: ∆ABC~∆PQR, CORRESPONDING ANGLES OF SIMILAR TRIANGLES)

Answer 2

Hello, Buddy!!

||Required Response||

Given,

∆ABC ~ ∆PQR

∠ABC = 70° & ∠BAC = 50°

By Corresponding Parts of Similar Triangles

∠ABC = ∠PQR

∠BAC = ∠QPR

∠BCA = ∠PRQ

AB/PQ = BC/QR = CA/RP

Value of ∠PQR

• $\longmapsto\;\red{\bold{70°}}$

$\boxed{\tt{@MrMonarque}}$

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