If ∆ ABC ~ ∆ PQR, area of ∆ ABC = 81 sq.cm, area of ∆ PQR = 144 sq.cm and QR = 6cm, then length of BC is *
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area abc/area pqr = bc^2/qr^2=81/144
bc/qr = 9/12 = 3/4
bc/6 = 3/4
bc = 6×3/4=9/2
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