If ΔABC~ΔPQR, BC=8cm and QR =6cm, the ratio of the areas of ΔABC and ΔPQR
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The ratio of the areas of the similar triangle are in the ratio of the square of the corresponding sides
ar(∆ABC)/ar(∆PQR)=BC²/QR²
=8²/6²
=64/36
=16/9
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The ratio of the areas of the similar triangle are in the ratio of the square of the corresponding sides
ar(∆ABC)/ar(∆PQR)=BC²/QR²
=8²/6²
=64/36
=16/9
Mark as brainliest
thanx
Follow me guys
monishchandravamsi:
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Answered by
1
Answer:
Step-by-step explanation:
WKT,
Ratio of areas of 2similar triangles =squares of their corresponding sides.=(4/3)^2
=16/9
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