Question

If ∆ABC ~ ∆PQR if BC = 4 cm. And QR = 9 cm Find the ratio of the areas of ∆ ABC and ∆ PQR.​

Answer 1

$Given \: \triangle ABC \sim \triangle PQR$

$BC = 4 \:cm, \:and \: QR = 9 \:cm$

$We \:know \:that , \\\frac{Area \:\triangle ABC}{Area \:\triangle PQR} = \frac{BC^{2}}{QR^{2}}\\= \frac{4^{2}}{9^{2}}\\= \frac{16}{81} \\= 16 : 81$

Therefore.,

$\red { \frac{Area \:\triangle ABC}{Area \:\triangle PQR} }\green { = 16 : 81}$

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Answer 2

Answer:

It will be16:81

As we know that the the ratio of areas of similar triangles is equal to the square of their corresponding sides.

ar(∆ABC)/ar(∆PQR)=(BC/QR)^2. Hope it helps you