Question

If ΔABC ~ ΔQRP, ar (ΔABC) / ar (ΔPQR) =9/4 , AB = 18 cm and BC = 15 cm, then PR is equal to

(A) 10 cm (B) 12 cm (C) 20/3 cm (D) 8 cm​

Answer 1

Answer:

Given △ABC∼△QRP

Therefore,

$\frac{area \: triangle \: abc}{area \: triangle \: qrp} = \frac{bc2 }{pr2}$

or

$\frac{9}{4} = \frac{ {15}^{2} }{ {pr}^{2} }$

$or \: {pr}^{2} = \frac{ {15}^{2} \times 4}{9}cm$

Therefore,PR

$= \frac{15 \times 2}{3} = 10cm$

The correct answer is

a) 10

Step-by-step explanation:

Hope it will be helpful to you.