If ∆ ABC right angled at C angle A = 45° ,BC = 7 cm find angle B , angle AB and angle AC
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angle a + angle b + angle c = 180 ( sum angle property of the ∆)
now 45+90+ angle B= 180
now we get angle b = 45
and hence angle A = angle b
it is an isosceles right triangle
AC = BC = 7 cm
and as per pythogorous therom
(AB)^2 = (AC)^2 + (BC)^2
(AB)^2 = 7^2 + 7^2
that is (AB)^2 = 49 + 49
AB = root 98
now. we get AB as root 98
and
I hope it helps you mate
please thank me if u got it and mark as branliest answer.
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