Question

if ∆ ABC ~∆RQP angle A= 80° &angleB=60° what is the value of P

Answer 1

x+80+60=180
x+140=180
x=180-140
=40

Answer 2

<A +<B +<C= 180 (A.S.P.)
80+60+<C=180
<C=180-140
<C=40
since ABC~PQR
<P=<C
<P=40
HOPE IT HELPS ALL THE BEST