Question

if ∆ abc- ∆ rsm and if ab = 10 , bc=12 , rs= 5 find sm​

Answer 1

Here,

$\rm \large{∆ABC \sim ∆RSM}$

Given,

• AB = 10 cm
• BC = 12 cm
• RS = 5 cm
• SM = ?

We know,

$= > \rm{\frac{AB}{RS} = \frac{BC}{SM}} \\ \\ \rm= > SM = \frac{BC}{\frac{AB}{RS}} \\ \\ \rm= > SM = \frac{12}{ \frac{10}{5} } \\ \\ \rm= > SM = \frac{12 \times 5}{10} \\ \\ \rm= > SM = \frac{60}{10} \\ \\ \rm= > SM = \green{ 6 \: cm}$

Answer 2

Given : ∆ ABC ≈  ∆RSM

AB =10, BC=12,RS= 5

To Find : SM

Solution:

∆ ABC ≈  ∆RSM

corresponding sides of similar triangles are in same proportion

Hence

AB/RS  = BC/SM  = AC/RM

AB/RS = BC/ SM

=> 10/5  = 12 /SM

=> 2 = 12/SM

=> SM = 12/2

=> SM = 6

Length of SM = 6

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