Question

If ∆ ABC ,seg AD perpendicular to seg BC;angle C=45°,BD =5 and AC=8√2 then find AD​

Answer 1

Answer:

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm.

Answer 2

Answer:

cos 45= x/8_/2

x= 1/16_/2