If ∆ABC us right angled at C, then the value of cos(A+B) is
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0
Answer:
0°
Step-by-step explanation:
Sum of all the angles = 180°
∠C = 90° ⇒ (A+B) = 90°
∴ cos(A+B) = cos90°
= 0
Answered by
2
Step-by-step explanation:
• ∆ABC is right angled at C.
•The value of cos(A + B).
Since , ∆ABC is right angled at C
∴ ∠C = 90°
:A + B + C = 180
:A + B + 90
:cos ( a + b ) = cos 90°
:
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