If ABCD is a cyclic a. quadrilateral, prove that
cotA + cotB + cotC + cotD = 0
Answers
Answered by
14
Answer:
Step-by-step explanation:
ii) So if ABCD is a cyclic quadrilateral taken in order, then A + C = 180° and B + D = 180°
==> A = (180 - C)
==> cos(A) = cos(180 - C) = -cos(C)
==> cos(A) + cos(C) = 0 ------ (1)
Similarly it can be shown that cos(B) + cos(D) = 0 ----------- (2)
Adding (1) & (2): cos(A) + cos(B) + cos(C) + cos(D) = 0 [Proved]
Anonymous:
hy
Nice answer respected ma'am.....Plz give me blessings. I touch ur feet ma'am
Thanks! No need to touch feets we are friends ;)
but ma'am u are ranked high u are expert and I am helping hand thats why I touch ur feet
No need! Friends = Friends Any rank doesn't matter RESPECT IS RESPECT! And we are humans ;) Human can't be perfect
u are very humble mam..thank you
^_^
Similar questions