Question

If ABCD is a cyclic quadrilateral such that
12 tan A - 5 = 0 and 5 cos B +3=0 then
cos C tan D =​

Answer 1

Answer:

Step-by-step explanation:

here is your answer

Answer 2

Answer:

-16/13

Step-by-step explanation:

A + C = 180, B + D = 180

Tan A = 5/12 (where 0 < A < pi/2 and pi/2 < C < pi)

cos B = -3/5 < 0 (where pi/2 < B < pi and 0 < D < pi/2)

Cos C = -12/13; Tan D = 4/3

cos C * Tan D = -12/13 * 4/3 = -16/13