English, asked by abhi2524, 11 months ago

if ABCD is a cyclic quadrilateral then cos (180 + A) + cos (180-B) +cos(180-C) + sin(90-D) with explanation ​

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Answered by tanmaya2134
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Answer:

cos(180+A)+cos(180-B)+cos(180-C)+sin(90-D)=0

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