Question

if ABCD is a parallelogram and Angle A=80° and Angle CBD = 65° find the angles of the parallelogram and ∆ABD​

Answer 1

Answer:

Angle DAB = 80*  

angle DBA = 35*

angle ADB = 65*

Step-by-step explanation:

angle a = 80* ( given)

angle b = 65*(given)

angle d = angle b ( alternate interior angles)

angle DAB + angle DBA + angle BAD = 180* ( angle sum property)

80* +  angle DBA + 65* = 180*

angle DBA + 145* = 180*

angle DBA = 180* - 145*

angle DBA = 35*