If ABCD is a parallelogram. angle ADE= 50 and angle ACE= angle BED=90. Find angle EAC + angle ABC- 2 angle DAC
a) 20 degree
b) 10 degree
c) 30 degree
d) 40 degree
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Thank you for asking this question. Here is your answer:
We know that the Angle BED = 90°
And Angle AEC = 45°
Then the Angle EAB = 45°
Angle ABC is equal to 45°
Angle ADE = 50°
And Angle DAC = 40°
Angle EAC+ Angle ABC - 2 Angle DAC = 45° +45°-2×40°
= 90° - 80°
= 10°
So the final answer for this question is 10°
If there is any confusion please leave a comment below.
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