if ABCD is a parallelogram p is a point as a research that EP equal to 1 by 3 and q is a point is bc such that PQ equal to 1 by 3 PC then AQCP is a
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AD = BC (opposite sides of parallelogram ABCD)
therefore , 1/3 AD = 1/3 BC (both sides of the equation are divided by 3)
so, AP = CQ (substitution) - 1
also , AP is parallel to CQ because AD is parallel to BC and A-P-D , B-Q-C (that is they are in a straight line) - 2
so by 1 and 2 , AQCP is a parallelogram (a pair of opposite sides test)
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