If ABCD is a parallelogram , then prove that ΔABD is congruent to ΔCDB.
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Step-by-step explanation:
GIVEN
ABCD is a parallelogram.
In ∆ABD and ∆CDB
DB = DB. ( Common)
DC = AB. (Opp.Sides of parallelogram)
AD = BC. (Opp. sides of parallelogram)
By SSS rule,
∆ABD is congruent to ∆CDB
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