If abcd is a parallelogram, then prove that: ar(abc)=ar(abc)=ar(abc)=ar(pcd) = 1/2 ar(^gm abcd)
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Step-by-step explanation:
Given,
abcd is a parallelogram
Construction,
draw a line from a to d
Solution,
ab=cd ( opposite sides of a parallelogram)
ac=ac( common diagonal)
bc=ad ( opposite sides of a parallelogram)
therefore triangle abc is congruent to triangle adc by sss congruence rule
therefore ar(abc)= ar(adc) ( two congruent triangles have equal areas)
ar(abc)+ar(adc) = ar abcd
since , ar(abc)= ar(adc)
therefore ar(abc)=1/2 ar(abcd) hence proved
Answered by
2
Step-by-step explanation:
Hope it Helps !
Priyanshu Kumar Singh [ Student ; Trinity Global school ]
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