if ABCD is a parallelogram,then prove that ar(ABD)=ar( BCD)=ar(ABC)=ar(ACD)=1/2ar(parallelogram ABCD)
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Answer:
Step-by-step explanation:
We know that,
Diagonal of parallelogram divides it into two quadrilaterals.
Since,
AC is the diagonal
Then, Area (ΔABC) = Area (ΔACD)
=
Area of parallelogram ABCD (i)
Since,
BD is the diagonal
Then, Area (ΔABD) = Area (ΔBCD)
=
Area of parallelogram ABCD (ii)
Compare (i) and (ii), we get
Therefore,
Area (ΔABC) = Area (ΔACD) = Area (ΔABD) = Area (ΔBCD) =
Area of parallelogram ABCD
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