Question

If ABCD is a parallelogram then prove that Triangle ABCD is congurent to triangle CDB​

Answer 1

Step-by-step explanation:

AB=CD (opposite sides of a parallelogram are equal)

AC=BD(opposite sides of a parallelogram are equal)

NOW,

IN TRIANGLE ABD AND TRIANGLE CDB

CD=CD (common)

AB=CD(proved above)

AC=BD(proved above)

Therefore, triangle ABD is congruent to triangle CDB

thanks

Answer 2

Step-by-step explanation:

AB=CD (opposite sides of a parallelogram

are equal)

AC=BD(opposite sides of a parallelogram are equal)

NOW,

IN TRIANGLE ABD AND TRIANGLE CDB

CD=CD (common)

AB=CD(proved above)

AC=BD(proved above)

Therefore, triangle ABD is congruent

to triangle CDB