if ABCD is a quadrilateral, then sec²(A+B/4)-cot²(C+D/4)=?
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If ABCD is a quadrilateral then tan(4A+B)=
A
cos(4C−D)
B
−cot(4C−D)
C
cot(4C+D)
D
−cot(4C+D)
Answer
ABCD is a quadrilateral.
We know, sum of four angles of a quadrilateral is 360o.
⇒ A+B+C+D=360o
⇒ A+B+C+D=2(180o)
⇒ A+B+C+D=2π
⇒ A+B=2π−(C+D)
Dividing both sides by 4 we get,
⇒ 4A+B=2π−4C+D
Multiplying both sides by tan we get,
⇒ tan(
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