Math, asked by rani1861, 1 year ago

If ABCD is a rectangle and ma angle ADB=(x+15)° and m angle BDC=(2x+3)° then x is ?

Answers

Answered by Anonymous
0
\mathfrak{\huge{Answer:}}

Given:

Angle ADB = x + 15°

Angle BDC = 2x + 3°

To find:

Value of x

Solution:

As we know,
\textbf{In a rectangle, all the angles are equal to 90°.}

Therefore:-

Angle ADC = 90° ...(1)

Angle ADC = Angle ADB + Angle BDC ...(2)

(1) = (2)

=》 90° = x + 15° + 2x + 3°

=》 90° = 3x + 18

=》 90 - 18 = 3x

=》 72/3 = x

=》\textbf{x = 24}
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