If ABCD is a rectangle and ma angle ADB=(x+15)° and m angle BDC=(2x+3)° then x is ?
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Given:
Angle ADB = x + 15°
Angle BDC = 2x + 3°
To find:
Value of x
Solution:
As we know,
Therefore:-
Angle ADC = 90° ...(1)
Angle ADC = Angle ADB + Angle BDC ...(2)
(1) = (2)
=》 90° = x + 15° + 2x + 3°
=》 90° = 3x + 18
=》 90 - 18 = 3x
=》 72/3 = x
=》
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