If abcd is a rectangle and o is the intersection point of diagonls,if oa =9cm and bd=?
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ABCD is a rectangle.
AC and BD are joined while O is the intersecting point
In Triangles ADC and BCD
AD=BC (opposite sides of rectangle are equal)
Angles ADC= BCD = 90°
DC = DC(Common side)
Hence, Triangles ADC is congruent to BCD
(AD = BC (By C.P.C.T.C)
ADC - OCD = BCD - OCD (Subtracting Triangle OCD from both sides)
AOD = BOC (proved))
We can also say
AOD is congruent to BOC (By A.A.S)
( Angles ADO = OBC (Interior alternate angles)
AOD = BOC (Vertically Opposite angles)
AD = BC (Opposite sides of rectangle are equal))
Therefore,
OB = OD (BY C.P.C.T.C)
OD = OC (By C.P.C.T.C)
AC - OC = BD - OC (Since OD = OC)
OA = OB
OB = 9cm
BD = OB + OD
= 9 cm.
= OB + OB (Since OB = OD proved above)
= 9cm + 9cm=18 cm( Ans)
AC and BD are joined while O is the intersecting point
In Triangles ADC and BCD
AD=BC (opposite sides of rectangle are equal)
Angles ADC= BCD = 90°
DC = DC(Common side)
Hence, Triangles ADC is congruent to BCD
(AD = BC (By C.P.C.T.C)
ADC - OCD = BCD - OCD (Subtracting Triangle OCD from both sides)
AOD = BOC (proved))
We can also say
AOD is congruent to BOC (By A.A.S)
( Angles ADO = OBC (Interior alternate angles)
AOD = BOC (Vertically Opposite angles)
AD = BC (Opposite sides of rectangle are equal))
Therefore,
OB = OD (BY C.P.C.T.C)
OD = OC (By C.P.C.T.C)
AC - OC = BD - OC (Since OD = OC)
OA = OB
OB = 9cm
BD = OB + OD
= 9 cm.
= OB + OB (Since OB = OD proved above)
= 9cm + 9cm=18 cm( Ans)
kinkyMkye:
*facepalm*
Answered by
0
Answer:
BD =18 cm is the answere
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