Question

if ABCD is a rectangle angle aob = 28 degree find angle OBC

Answer 1

AC=DB (Diagonal of rectangle )
1/2AC=1/2DB
it means AO=OB
Angle OBA=28degree (because angle opp. to equal side are equal)
Angle ABC=Angle OBC+Angle ABO
90=Angle OBC+28
Angle OBC=62 Degree
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Answer 2

given,
ABCD is a rectangle
angle AOB = 28 degree
DB and AC are diagonal
So, Triangle AOB is an isosceles triangle
So,
angle OAB= angle ABO= 28 degree
now,
28 degree+ angle OBC= 90 degree [ABCD is a rectangle]
=>angle OBC= 90-28 degree
=> angle OBC= 62 degree

So the value is angle OBC= 62 degree

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