if abcd is a rectangle find x and y..ab=30cm,bc=x-y cd= x+y da=14cm
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In a rectangle, opposite sides are equal.
So, ab=cd
or,30=x+y
or,x+y=30-----------(i)
Likewise,
bc=da
or,x-y=14-----------(ii)
Now,Solving eq. (i) & (ii):
x+y=30
x-y=14
______________
or,2x=34
or, x=34/2
∴ x=17
Then, in eq. (i):
x+y=30
or,17+y=30
or, y=30-17
∴ y=13
So, ab=cd
or,30=x+y
or,x+y=30-----------(i)
Likewise,
bc=da
or,x-y=14-----------(ii)
Now,Solving eq. (i) & (ii):
x+y=30
x-y=14
______________
or,2x=34
or, x=34/2
∴ x=17
Then, in eq. (i):
x+y=30
or,17+y=30
or, y=30-17
∴ y=13
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