if ABCD is a rhombus and diagonalAC and BD intersected at O. if angle OAB=55degree .find the angle of the rhombus
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angle OAB =55°
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angle DAB = 55*2-110° [diagonals of rhombus bisect the vertex angles] angle DAB = angle DAB =110° [properties of a parallelogram as rhombus is a parallelogram]
angle ABC = 180- angle DAB= 180-110=70° Angle ADC= angle ABC = 70°
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