Question

If ABCD is a rhombus and diagonals AC and BD intersect at O. If angle OAB=55 degree , find the angles of the rhombus.
pls solve with proper steps​

Answer 1

Answer:

Step-by-step explanation:

angle OAB =55°

angle DAB = 55*2=110° [diagonals of rhombus bisect the vertex angles]

angle DAB = angle DAB =110° [properties of a parallelogram as rhombus is a parallelogram]

angle ABC = 180- angle DAB= 180-110=70°

Angle ADC= angle ABC =70°

Answer 2

Answer:

angle OAB =55°

angle DAB = 55*2=110° [diagonals of rhombus bisect the vertex angles]

angle DAB = angle DAB =110° [properties of a parallelogram as rhombus is a parallelogram]

angle ABC = 180- angle DAB= 180-110=70°

Angle ADC= angle ABC =70°

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