Question

if ABCD is a rhombus bm = 3and mc = 4 then the perimeter of ABCD is ?​

Answer 1

perimeter = 20 cm

let diagonal of rhombus meet at m

in ∆ BMC

square of BC= square of mc+square of BM

square of BC=16+9

BC=√25

BC=5 cm

as you know rhombus has equal sides

then perimeter will be 20 cm

I hope u understand

Answer 2

Answer:

10 m

Step-by-step explanation:

on applying Pythagoras theorem, find side of rhombus. And we know that perimeter= 4 ×side of rhombus