Question

if ABCD is a rhombus diagonal AC and BD intersect at O and E is point lying on the circle with center O then the sum of angle BAE and EDC

Answer 1

AC is diameter of circle.
So , a(ABC) = 90°
But ∆ABC is an isosceles ∆ with AB = BC So, a(BAC) = a(BCA) = 90/2 = 45°
a(BAC) = a(BDC) = 45°
Also , a(BAE) = a(BDE)
a(BAE) + a(EDC) = a(BDE) + a(EDC) =
a(BDC) = 45°