if ABCD is a rhombus, find the measure of angle ADC, given that angle BAC is 55
Answers
Answered by
118
As we know that the diagonal are the angel bisector of rhombus.
So, diagonal AC bisects ∠BAD
∴∠BAD = 2∠BAC = 2×55° = 110°
Now, ∠BAD + ∠ADC = 180° ( parallel line property)
⇒∠ADC = 180°- 110° = 70°
So, diagonal AC bisects ∠BAD
∴∠BAD = 2∠BAC = 2×55° = 110°
Now, ∠BAD + ∠ADC = 180° ( parallel line property)
⇒∠ADC = 180°- 110° = 70°
Answered by
130
Answer:
Step-by-step explanation:
Given :-
BAC = 55°
To Find :-
∠ ADC
Formula to be used :-
Angle sum property and Opposite angle of a rhombus are equal.
Solution :-
In rhombus ABCD
AB = AC
⇒ ∠BAC = ∠BCA = 55°
In ∆ ABC, we have
⇒ BAC + BCA + ABC = 180° [∠ sum property]
⇒ 55° + 55° + ABC = 180°
⇒ 110° + ABC = 180°
⇒ ABC = 70°
As we know that opposite angle of a rhombus are equal.
⇒ ABC = ADC = 70°
Hence, measure of ADC is 70°.
Similar questions