If ABCD is a rhombus, prove that
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hay!!
Dear user -
in given ABCD rhombus 4ab²
Than prove that ac²+bd²
we use this figure
so,
OA=1/2AC,OB=1/2BD
and △ AOB=90
in Right △AOB, using the above theorem
AB²=OA²+OB²
=> (1/2AC)²+(1/2BD)²
=> AC²+BD²
so,
Hence 4ab²=ac²+bd²
I hope it's help you
Dear user -
in given ABCD rhombus 4ab²
Than prove that ac²+bd²
we use this figure
so,
OA=1/2AC,OB=1/2BD
and △ AOB=90
in Right △AOB, using the above theorem
AB²=OA²+OB²
=> (1/2AC)²+(1/2BD)²
=> AC²+BD²
so,
Hence 4ab²=ac²+bd²
I hope it's help you
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