if ABCD is a square and DC is equal equal Triangle in the figure then angle DAE is equals to
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here , the triangle is equilateral so the figure is formed as a regular Pentagon so angle ADE here is 90°+60° = 150° ,
and AD = DE
SO angle DAE = angle DEA = x. so,
150 + 2 x = 180°. (angle sum property)
2x = 30°
x = 15°
hope it helped you
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Step-by-step explanation:
Therefore, angle DAE is equal to 90°-80°=10°. Therefore, angle DAE is equal to 10°. To prove:angle DAE=? Solution: In square ABCD,angle A=90degree,angle B=90 degree, angle C=90 degree and angle D=90 and all sides are equal to each other.
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