If ABCD is a square then show that the points A, B, C and D are concyclic.
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Answer with explanation:
It is given that , ABCD is a Square.
Measure of each of interior Angles of Square is 90°.
That is, ∠A=∠B=∠C=∠D=90°
Now , sum of Opposite angles
∠A + ∠C
= 90° + 90°
=180°
Also, ∠B + ∠D
== 90° + 90°
=180°
If you plot a Quadrilateral, passing through points , A , B, C and D ,
Then, ∠A + ∠C=180°
as well as , ∠B + ∠D=180°
Showing that points , A, B, C and D are Con-cyclic.
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