if ABCD is a square where A(0,0 ). B(2, 0) D( 0,2 ) , then the coordinate of C is
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17
Answer:
Step-by-step explanation:
Let us take a Square ABCD :
We know in a Square Diagonals Bisect each other;
So Let the two Diagonals be AC and BD;
Mid Point of AC = Mid Point of BD.
Coordinates of A(0,0),B(2,0) & D(0,2)
Let Coordinates of C be (x,y);
Mid Point of AC =
(0+x)/2 , (0+y)/2 = (x/2 , y/2)
AND
Mid Point of BD =
(2+0)/2 , (0+2)/2 = 2/2 , 2/2 = (1,1)
By Equating both the Mid Points we get:
(x/2 , y/2) = (1,1)
x/2 = 1 & y/2 = 1
So,
x = 2 & y = 2
Hence the coordinates of C are (2,2).
Answered by
4
Answer:
Step-by-step explanation:
We know that diagonals of a square bisect each other.
Therefore, use the formula for finding the mid-point.
The complete answer is below here
Hope it helps
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