Math, asked by namrathadobbali, 5 months ago

if ABCD is cyclic trapezium in which AD parallel to BC and angle B = 60°, then angle BCD is equal to​

Answers

Answered by Anonymous
7

Answer:

as the trapezium is cyclic it is also isosceles

and the base angles are equal in measure......

therefore,

angle B = angle C = 60°

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