if abcd is rhombus and digonals ac and bd intersect at o if angle oab =55
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Answer:
angle OAB =55°
angle DAB = 55*2=110° [diagonals of rhombus bisect the vertex angles]
angle DAB = angle DAB =110° [properties of a parallelogram as rhombus is a parallelogram]
angle ABC = 180- angle DAB= 180-110=70°
Angle ADC= angle ABC =70°
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