Math, asked by zahidmon3517, 2 months ago

If ABCD isa rhombus with ∠ABC = 56o, find ACD.

Answers

Answered by kritiShrivastava
0

Answer:

Angle ACD = 62°

Step-by-step explanation:

Given, ABCD is a rhombus

Angle ABC = 56°

Solution, Angle BCD = 180° - 56° or 124° (Alternate angle)

Now, Diagonals of rhombus bisect the angle.

Therefore, Angle ACD = Angle BCA

Since, Angle ACD + Angle BCA = 124°

Angle ACD + Angle ACD = 124°

2(Angle ACD) = 124°

Angle ACD = 124°/2

Angle ACD = 62°

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