If ABCD isa rhombus with ∠ABC = 56o, find ACD.
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Answer:
Angle ACD = 62°
Step-by-step explanation:
Given, ABCD is a rhombus
Angle ABC = 56°
Solution, Angle BCD = 180° - 56° or 124° (Alternate angle)
Now, Diagonals of rhombus bisect the angle.
Therefore, Angle ACD = Angle BCA
Since, Angle ACD + Angle BCA = 124°
Angle ACD + Angle ACD = 124°
2(Angle ACD) = 124°
Angle ACD = 124°/2
Angle ACD = 62°
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