If ABCD rectangle , E F are the mid points of BC and AD respectively and G is any point on EF , then ar triangle GAB equals ??
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Given that E and F are mid-points of BC and AD respectively
ar(□ABFE)= 1/2 ar(□ABCD)[∵ E and F are mid points of BC and AD respectively]
ar(△GAB)= 1/2ar(□ABFE)[∵ Area of triangle is half of area of rectangle on the same base and between the same parallels]
=1/2× 1/2 ar(□ABCD)
=1/4ar(□ABCD)
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